Derivation for three dimensional steady state heat conduction equation with internal energy of cylinder? - steady heat tech deck
haet with internal energy
Tuesday, December 8, 2009
Steady Heat Tech Deck Derivation For Three Dimensional Steady State Heat Conduction Equation With Internal Energy Of Cylinder?
1 comment:
Well, if you use the heat that is applied at one end, and have removed the other is the temperature between the two extremes linear. Just change the temperature along the axis, not radially.
Start with dQ / dt = kAdeltaT Note that K and A are the same everywhere, as dQ / dt, and the solution on the right side.
At steady state the internal energy does not matter, because it will not change.
Of course, if the heat flow from one extreme to the more complicated things d'autres ... You must change your question.
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